Question

In an experiment, a boy took a solid iron cuboid of force 30N and dimensions 30cm X 20cm X 10cm .The minimum pressure exerted on the table will be? ​

Answer 1

Answer:

333.33...

Explanation:

We converted all the units in SI system.........

Force = 30N.....(Already in SI)

Dimension first = 30 cm = 0.3 m

Dimension second = 20 cm = 0.2

Dimension third = 10 cm = 0.1 m

When cuboid is placed from its one side, it becomes a square

(I) Area of first dimension (square) = 0.3 × 0.3

= 0.09 m²

Pressure = Force/area

Pressure on first dimension = 30/0.09

= 333.33..... Pascal

(II) Area of second dimension (square) = 0.2 × 0.2

= 0.04 m²

Pressure = Force/area

Pressure on second dimension = 30/0.04

= 750 Pascal

(III) Area of third dimension = 0.1 × 0.1

= 0.01 m²

Pressure on third dimension = Force/area

= 30/0.01

= 3000 Pascal

Since, 333.33... < 750 < 3000

The minimum pressure on the table will be 333.33... Pascal