Question

In an experiment a steel specimen of 13mm diameter was found to elongate 0.2mm in a 200 mm gauge length when it was subjected to a force of 26.8 KN. If specimen was tested within elastic range, Calculate Young's modulus for the steel​

Answer 1

Answer:

Step-by-step explanation:

Given:- Diameter (d) = 13mm , Elongation = 0.2 , Length(l)=200mm,Force (p) = 26.8KN

Let,

E= Value Of Young's Modulus For The Steel Specimen

We Know that cross-sectional area of specimen

A=3.14*d^²/4= 3.14*169/4 = 132.73mm²

Elongation of Specimen = pl/A.E

0.2*E=26.8*200/132.73

E = 40.38/0.2

E=201.9 Gpa

Answer 2

Answer:

In an experiment, a steel specimen of 13 mm diameter was found to elongate 0.2 mm in a 200 mm gauge length

when it was subjected to a tensile force of 26.8 KN. If the specimen was tested within elastic range, what is the

value of Young’s modulus for the steel specimen? (Hint: Use the formula for deformation)