Question

In an experiment an iron sphere of mass 390 g displaces 5cm3 of water. What is the density of iron? Ans 78g / cm3. Process?​

Answer 1

Answer:

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Explanation:

$so \: here \: \\ mass \: of \: iron \: sphere \: (m) = 390.g \\ volume \: of \: water \: (v) = 5.cm {}^{3} \\ \\ so \: we \: know \: that \\ density = \frac{mass}{volume} \\ \\ density \: of \: iron = \frac{mass \: of \: iron \: sphere}{volume \: of \: water} \\ \\ = \frac{390}{5} \\ = 78 \\ = 78. \: \frac{g}{cm {}^{3} }$