Question

In an experiment, hydrochloric add was reacted with calcium carbonate at STP
and 80cm of carbon dioxide was produced, Calculate the number of molecules
of carbon dioxide given off.

Answer 1

CaCO 3 +2HCl→CaCl 2 +H 2 O+CO 2 100 g 44 g1 mole 1 mole22.4 L 22.4 LWe know that 1 mole of any gas at 0 o C and 1 atm pressure occupies 22.4 L volume.

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Answer 2

What mass of CO2 gas would be produced if 10g of calcium carbonate reacted with access of hydrochloric acid?

CaCO3+2HCl→CaCl2+H2O+CO2

mCaCO3=10

MrCaCO3=40+12+16⋅3=100

n=mMr

nCaCO3=10100=0.1

The amount of moles should be proportional to the coefficient in the reaction. Since both CaCO3 and CO2 have the same coefficient:

nCO2=0.1

MrCO2=12+16⋅2=44

mCO2=0.1⋅44=4.4 g