In an experiment it showed that 10 mL of 0.05 M solution of chloride required 10 mL of 0.1 M solution of AgNO₃, which of the following will be the formula of the chloride (X stands for the symbol of the element other than chlorine):
(a) X₂Cl
(b) X₂Cl₂
(c) XCl₂
(d) XCl₄
Answers
Answer:
(c) XCl2 is the correct answer.
Explanation:
Volume of chloride solution : 10 mL of molarity of chloride : 0.05 M
molarity of AgNO3 = 0.1 M
To find:
formula of the chloride (X stands for the symbol of the element other than chlorine)
Molarity = moles/volume
0.05= moles/10/1000
Number of moles of chloride solution=
0.05/1000
The number of moles of AgNO3=
Molarity*volume
=0.1*10/1000
=1/1000
We also need to calculate
Gram equivalent of AgNO3
=n factor*moles
=1*1/1000
According to the question
Grams equivalent of chloride=
Grams equivalent of AgNO3
0.5n/1000= 1/1000
Cancelling 1000 from denominator
0.5n =1
Thus n=2
Hence according to the question
Formula is XCl2
Ans of chloride is XCl2.
Gram equivalent is the mass of given required compound.
Molarity is Number of moles per 1 litre of solution.
Answer:
C
Explanation: