Question

In an experiment of maths frustum of cone is made up of from seven Rings the radius of uppermost ring is 4 centimetre and the radius of a each ring is increased by 1 cm so that the radius of last ring is 10 cm if the width of it each ring is 3 cm then find the volume of entire frustum avoid the spaces between rings​

Answer 1

Answer:

The Volume of frustum made is 3432 cm³.

Step-by-step explanation:

Given: Frustum is made up of 7 rings.

           Radius of  top ring is 4 cm and Radius of bottom ring is 10 cm.

           Radius increase by 1 cm.

           Width of ring is 3 cm.

To find: Volume of frustum made.

Formula for volume of frustum = $\frac{1}{3}\pi\times h\times(R^2+r^2+Rr)$

Radius of Top ring, r = 4 cm

Radius of Bottom ring, R = 10 cm

Height of ring, h = 7 × 3 = 21 cm

Putting these value in formula, we get

Volume of Frustum = $\frac{1}{3}\times\frac{22}{7}\times21\times(10^2+4^2+10\times4)$

                                = $22\times(100+16+40)$

                                = $22\times(156)$

                                = 3432 cm³

Therefore, the volume of frustum made is 3432 cm³.