Question

in an experiment of throwing a die 100 times , 3 was received 18 times. find the probability of receiving 3 in an expriment of throwing a die.​

Answer 1

Step-by-step explanation:

Given:In an experiment of throwing a die 100 times , 3 was received 18 times.

To find : The probability of receiving 3 in an experiment of throwing a die.

Solution:

We know that

$\bold{Probability \: of \: an \: event = \frac{Favourable \: outcomes}{Total \: number \: of \: outcomes} }$

Thus,

In the experiment of throwing a die 100 times , 3 was received 18 times.

So,

Probability of getting three is =18/100= 0.18

(In this particular case)

But,

To find the probability of receiving 3 in an experiment of throwing a die.

Since total no of outcomes in a dice= 6

{1,2,3,4,5,6}

Favourable outcome =1 i.e.{3}

$P(3) = \frac{1}{6}$

Thus,

Probability of getting 3 in an experiment of rolling a dice is 1/6.

Hope it helps you.

Answer 2

Step-by-step explanation:

Given:In an experiment of throwing a die 100 times , 3 was received 18 times.

To find : The probability of receiving 3 in an experiment of throwing a die.

Solution:

We know that

\begin{gathered}\bold{Probability \: of \: an \: event = \frac{Favourable \: outcomes}{Total \: number \: of \: outcomes} } \\ \\ \end{gathered}

Probabilityofanevent=

Totalnumberofoutcomes

Favourableoutcomes

Thus,

In the experiment of throwing a die 100 times , 3 was received 18 times.

So,

Probability of getting three is =18/100= 0.18

(In this particular case)

But,

To find the probability of receiving 3 in an experiment of throwing a die.

Since total no of outcomes in a dice= 6

{1,2,3,4,5,6}

Favourable outcome =1 i.e.{3}

\begin{gathered}P(3) = \frac{1}{6} \\ \\ \end{gathered}

P(3)=

6

1

Thus,

Probability of getting 3 in an experiment of rolling a dice is 1/6.