Question

In an experiment on meter bridge, if the balancing length ac is x, what would be its value, when the radius of the meter bridge wire ab is doubled? Justify your answer.

Answer 1

it's answer will be,

$x2 = \frac{100x1}{400 - 3x1}$

Answer 2

Answer:

Explanation:

The value of the balancing length l will remain the same even if the radius of the meter bridge wire is doubled, provided the area of cross section of the wire is uniform. This is because the relation R/X = l/(100−l) is independent of the area of cross section of the wire. (X is the unknown resistance).