in an experiment on meter bridge if the balancing length AC is X what would be its value when the radius of the meter bridge wire is doubled?
Answers
Here is the answer to this question:
Explanation:
Suppose AC =x and the segments are AC and BC are RAC and RBC respectively.
Now, let’s suppose the condition of no deflection as
R/r = RAC/RBC
If the resistance of AB is multiplied, the ratio of R/r or RAC/RBC will remain the same.
Therefore, the final balancing length of AC= x will stay the same.
In an experiment on meter bridge if the balancing length AC is X and when the radius of the meter bridge wire is doubled, then the value of the balancing length AC will remain same i.e. it will be X only.
Explanation:
Consider the the Bridge meter having Resistors R1 and R2
and consider he resistance of segments AC and BC are RAC and RBC respectively.
In case of meter Bridge, when the Galvanometer shows null deflection, then
R1/RAC=R2/RCB
By rearranging we get
R1/R2=RAC/RCB
R1/R2= x/(100−x)
When the radius of the wire is doubled, then the resistance of CB will change.
But since R1/R2 does not change, so RAC/RCB should also not change at balancing point.
Hence, the point C will not change and the final balancing length of AC= x will remain the same.