Question

In an experiment on the specific heat capacity of solid, a 200gm block of metal at 15°c is dropped in a copper calorimeter of mass 270 gm containing 150 cm3 of water at 27°c. The final temp. is 40°C, calculate the specific heat capacity of solid.

Answer 1

Answer:

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Explanation:

☆Mass of the metal, m = 0.20 kg = 200 g

Initial temperature of the metal, T

1 = 150 oC

Final temperature of the metal, T 2= 40oC

Calorimeter has water equivalent of mass, m = 0.025 kg = 25 g

Volume of water, V = 150 cm3

Mass (M) of water at temperature T = 27

oC:150×1=150g

Fall in the temperature of the metal:ΔT

m=T

1 -T2

=150−40=110 oC

Specific heat of water, C w=4.186J/g/K

Specific heat of the metal =C

Heat lost by the metal, =mCT .... (i)

Rise in the temperature of the water and calorimeter system: T

1 −T=40−27=13 oC

Heat gained by the water and calorimeter system: =m1

C w T=(M+m)C w

..Heat lost by the metal = Heat gained by the water and colorimeter system

mCΔT ,m =(M+m)C

wT w 200×C×110=(150+25)×4.186×13

C=(175×4.186×13)/(110×200)=0.43Jg −1

k−1If some heat is lost to the surroundings, then the value of C will be smaller than the actual value.