Question

In an experiment the count of bacteria grows by 5% in the first hour gets destroyed by 5% in the second hour and again grows by 5% in the third hour if the count at the end of the third hour is 8.379×10^8the original count of bacteria is

Answer 1

Answer:

8.379×10^8 - .41895 × 10^8

please mark me as brainlist....

Answer 2

OK FRIEND HERE IS YOUR ANSWER:

GIVEN:

the count of bacteria grows by 5% in the first hour gets destroyed by 5% in the second hour and again grows by 5% in the third hour if the count at the end of the third hour is 8.379×10^8.

TO FIND:

The original count

SOLUTION:

Let the original count=x

Now, According to the question:

Bacteria grows in the first hour=5% of x

=5/100 × x

=5x/100

Now,

Bacteria reduces in the second hour=5% of 5x/100

=5/100 × 5x/100

=x/400

Now,

Bacteria grows in the third hour= 5% of x/400

=5/100 × x/400

=x/8000 (equation 1)

Now, According to the question:

The count at the end of the third hour is 8.379×10^8.

Now, From equation 1:

x/8000 = 8.379 × 10^8

x/8000 = 8.379 × 100000000

x/8000 = 837900000

x = 837900000 × 8000

x = 6703200000000

OR

x = 67032 × 10^8 ANSWER☺

HOPE IT HELPS YOU

IF IT HELPED YOU PLEASE FOLLOW ME AND MARK ME AS BRAINLIEST AND DON'T FORGET TO THANKS PLEASE

EXPECTATION ATLEAST 30 THANKS PLEASE PLEASE