Question

In an experiment, to determine the percentage purity of the hydrochloric acid, 25cm3 of the acid solution made by dissolving 25.5g of impure acid in a liter of solution was found to neutralize 25cm3 of 0.4M NaOH solution. Calculate a. Concentration of the acid in (i) g/dm3 (ii) mol/dm3 b. percentage purity of the acid c. percentage impurity of the acid

Answer 1

Answer:

Explanation:

normality*volume=normality*volume

molarity*volume = molarity*volume

25*x = 10

x=10/25

moles of hcl = 0.4

weight = 16.4 g

percentage purity = 16.4/25*100

=65.6

ii)concentration of acid = molarity * molar mass

concentration of acid = 0.0164 g/ml

iii) 0.0004 mol / ml

iv)percentage impurity = 34.4