Question

In an experiment to determine volume of an object,mass & density are recorded as m= (5±0.15)kg & ρ=(5±0.2)kg/m3 respectively. Calculate percentage error in measurement of volume.

A) 7%
B) 7.5%
C) 0.7%
D) 8%

Answer 1

Answer:

A) 7%

Explanation:

The percentage error in  the measurement of volume is 7%.

Explanation:

Given that,

Mass = (5+0.15) kg

Density = (5+0.2) kg/m^3

We need to calculate the  percentage error in  the measurement of volume.

Using formula of volume

\dfrac{\Delta V}{V}\times100=\dfrac{\Delta M}{M}\times100}+\dfrac{\Delta \rho}{\rho}\times100

Put the value into the formula

\dfrac{\Delta V}{V}\times100=\dfrac{0.15}{5}\times100+\dfrac{0.2}{5}\times100VΔV×100=50.15×100+50.2×100

\dfrac{\Delta V}{V}\times100=7\%VΔV×100=7%

Hence, The percentage error in  the measurement of volume is 7%.