Question

 In an experiment to measure the speed of sound in air, a boy stands 40 m away from a wall and bangs two pieces of wood together. At the instant he hears the echo, he bangs them together again. He does this activity 50 times. The time taken for 50 bangs is 12 s. Which calculation gives the speed of sound in air? ​

Answer 1

Explanation:

distance=50×40×2 (as sound waves reflect)

=4000

time =12s

velocity =displacement/time

4000/12=333.3 m/s

Answer 2

Answer:

Here is your answer

40×2×50 upon 12

Explanation:

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