Question

In an experiment, width of given object was found to be 1.55 cm, 1.54 cm, 1.53 cm, 1.52 cm, 1.49 cm in successive trials. Calculate mean absolute error, relative error and percentage error.

Answer 1

thanks it will help you

Answer 2

Dear Student,

◆ Answer -

Mean absolute error = 0.0168 cm

Relative error = 0.01101

Percentage error = 1.101 %

● Explanation -

Mean of the given data is calculated by -

Mean = (1.55 + 1.54 + 1.53 + 1.52 + 1.49) / 5

Mean = 7.63 / 5

Mean = 1.526 cm

Mean absolute error is calculated as -

Mean absolute error = (|1.55-1.526| + |1.54-1.526| + |1.53-1.526| + |1.52-1.526| + |1.49-1.526|) / 5

Mean absolute error = (0.024 + 0.014 + 0.004 + 0.006 + 0.036) / 5

Mean absolute error = 0.084 / 5

Mean absolute error = 0.0168 cm

Relative error is calculated by -

Relative error = 0.0168 / 1.526

Relative error = 0.01101

Percentage error is calculated by -

Percentage error = 0.01101 × 100 %

Percentage error = 1.101 %

Hope this helps you...