In an experiment with Foucault's apparatus, the various distances used are as follows
Distance between the rotating and the fixed mirror = 16 m
Distance between the lens and the rotating mirror = 6 m,
Distance between the source and the lens = 2 m.
When the mirror is rotated at a speed of 356 revolutions per second, the image shifts by 0.7 mm. Calculate the speed of light from these data.
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The speed of the light is 2.975 × 108 m/s.
Explanation:
- Distance between the fixed and the rotating mirror (R) = 16 m
- Distance between the rotating mirror and the lens (b) = 6 m
- Distance between the lens and the source (a) = 2 m
- At a speed of 356 revolutions/second, the mirror rotates,
- ⇒ ω = 356 × 2 π rad/sec
- Image’s shift (s) = 0.7 × 103 m
- The speed of light in Foucault experiment is shown as c = 4R2was(R+b)
- =4 × (16)2 × 356 × 2π × 10-3(16+6) × 2(0.7) = 2.975 × 108 m/s
- So, the light’s speed is 2.975 × 108 m/s.
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