Question

In an experiment, zinc chlorate decomposed according to the following chemical equation.

Zn(ClO3)2 → ZnCl2 + O2

(Molar mass of Zn(ClO3)2 = 232.29 g/mol; ZnCl2 = 136.286 g/mol; O2 = 31.998 g/mol)

If the mass of zinc chlorate was 150 grams, which of the following calculations can be used to determine the mass of oxygen gas formed? (4 points)

Answer 1

Answer:

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Explanation:

5. (05.04 MC) In an experiment, zinc chlorate decomposed according to the following chemical equation. Zn(CIO3)2 -- ZnCl2 + O2 (Molar mass of Zn(CIO)2 - 232.29 g/mol; ZnCl2 - 136.286 g/mol; 02 - 31.998 g/mol) If the mass of zinc chlorate was 150 grams, which of the following calculations can be used to determine the mass of oxygen gas formed? (4 points) (150 x 1 x 232.29) + (31.998 x 3y grams (150 x 3 x 232.29) + (31.998 x 1) grams (150 x 1 x 31.998) + (232.29 x 3) grams (150 x 3 x 31.998) + (232.29 x 1) grams