Question

In an explosion, a body breaks up into two pieces of unequal masses. In this(a) both parts will have numerically equal momentum(b) lighter part will have more momentum(c) heavier part will have more momentum(d) both parts will have equal kinetic energy

Answer 1

The correct optipn regarding momentum is - (a) both parts will have numerically equal momentum

As per law of conservation of momentum, "For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision."

This states that momentum of a body remaines same before and after the collision.

Since initial velocity of body is zero. Initial momentum will be zero. Hence, new momentum of two bodies will p1 and p2.

As stated in law, sum should be zero, hence, p1 = -p2. Which can further be written as

m1v1 = -m2v2. Hence, both will be numerically same.

Answer 2

Answer:

both parts will have numerically equal momentum (A)