Question

In an half yearly examination 60% of the candidate failed in Physics and 40%

failed in Mathematics. If 15% of the candidate failed in both subjects and 7500
students passed in both then the total number of candidates are​

Answer 1

Answer:50000 candidates

Step-by-step explanation:

Let the total no of candidates be x

Candidates failed in maths=40%of x =40/100*x=2/5x

Candidates failed in physics =60%ofx=3/5x

People failed in both =15%ofx=3/20x

X=3/5x+2/5x+3/20×+7500=

3x/20=7500

X=7500×20÷/3

=50000

Answer 2

The total number of candidates are 50000.

Step-by-step explanation:

Consider the provided information.

Let n(A) represents the number of students failed in physics.

n(B) represents the number of students failed in math.

It is given that 60% of the candidate failed in Physics and 40%  failed in Mathematics. 15% of the candidate failed in both subjects.

Therefore,

P(A) = 60, P(B) = 40 and P(A∩B) = 15

n(A U B) = n(A) + n(B) - n(A ∩ B)

n(A U B) = 60 + 40 - 15

n(A U B) = 85

Hence, 85% students are failed.

Thus, the percentage of students passed in both of subject is:

100%-85%=15%

It is given that 7500  students passed in both subject.

Let the total number of students are x.

$x\times\frac{15}{100}=7500\\\\x=\frac{7500\times100}{15}\\\\x=50000$

Hence, the total number of candidates are 50000.

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