In an icosceles triangle ABC, the measure of vertex angle A is 30 more than the measure of each base angle .find the measure of each angle of the triangle
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angle b=angle c ( it is a icosceles triangle so 2 side are equal and angle opposite to equal sides are equal)
so, angle c=b=x
given that angle a is 30 more than the base angles so
a = 30+x
now by using angle some property
angle a+b+c =180°
(30+x)+x+x=180°
30+3x=180°
3x=180-30
x=150/3
x=50°
so,
angle a=30+50=80°
angle b=c=50°
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