Question

In an ideal transformer, the voltage and the current in the primary coil are 200v and 2a respectively. If the voltage in the secondary coil is 2000v, then the value of current in the secondary coil will be

Answer 1

Explanation:

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Answer 2

Answer:

In an ideal transformer, the voltage and the current in the primary coil are 200v and 2a respectively. If the voltage in the secondary coil is 2000v, then the value of the current in the secondary coil will be 0.2A

​Explanation:

• In a transformer, there is a primary coil with a number of turns $N_{1}$ voltage, and current through it is $I_{1}$. In the secondary coil, the number of turns is $N_{2}$ voltage is $V_{2}$ and current is $I_{2}$

• The relation connecting these parameters is given by the formula

        $\frac{N_{1} }{N_{2} } =\frac{V_{1} }{V_{2} }=\frac{I_{2} }{I_{1} }$

From the question, we have

the voltage in the primary coil is $V_{1} =200v$

the voltage in the secondary coil is $V_{2} =2000v$

the ratio of voltages $V_{1} /V_{2} =200/2000=1/10$

current in the primary coil $I_{1} =2A$

current in the secondary coil is ${I_{2} }={I_{1} }\frac{V_{1} }{V_{2} }$

⇒$I_{2} =2*1/10=0.2A$