Question

In an imaginary language , the digits 0,1,2,3,4,5,6,7,8 and 9 are substituted by a,b,c,d,e,f,g,h,i and j and 10 is written as ba

Answer 1

Hey dear,
You posted incomplete question.

◆ Complete question is -
In an imaginary language , the digits 0,1,2,3,4,5,6,7,8 and 9 are substituted by a,b,c,d,e,f,g,h,i and j and 10 is written as ba. Find ef×d-ba = ?

◆ Answer-
ef × d - ba = bcf => 125

◆ Explanation-
From given data-
ef => 45
d => 3
ba => 10

Solving ,
ef × d - ba => 45 × 3 - 10
ef × d - ba => 135 - 10
ef × d - ba => 125

125 can be written as bcf.

Therefore,
ef × d - ba = bcf => 125

Hope this helps...

Answer 2

Answer:

816 is the correct answer

Step-by-step explanation:

cd-23 ef-45 bc-12

(23+45)*12

68*12

816