Question

In an increasing sequence of 50 consecutive integers, the sum of first 25 integers is A. The sum of last 25 integers in the sequence is
a. 2A
b. A+25
c. A+50
d. A+625​

Answer 1

Answer:

Option d. A + 625 is the answer.

Step-by-step explanation:

According to the question, the sequence is increasing consectutively.

Hence, let them be;  x, x+1, x+2, x+3......x+49

Note; the last term is x+ 49 since the 50th term will have 49.

Therefore, Sum of first 25 = x .+ x+1. + x + 2......x+24

       Using the formula, Sn = n/2(a +l )

                                              = 25/2 ( x + x +24) =  25x + 300 = A

Similarly, the Sum of last 25 = x + 25. + x + 26.....x + 49

                                              = 25/2 ( x + 25 + x + 49) = 25x + 925

Now, comparing both the cases, we get,

Sum of last 25 = A + 625

HOPE THIS HELPS you....