In an infinite GP, every term is 7 times the sum of all the terms that follow. If the sum of the first and the second terms is 9, find the terms of the GP.
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a1= 9/8
a2= 63/8
There is one more GP in the given GP, with common ratio as 8 and first term as 63
The Nth term,when N=3,4,5 - - - - - - (For N=1,2 known)
a(N)= (63) * ( 8^(N-3) )
Answered by
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Answer:
a1= 9/8
a2= 63/8
There is one more GP in the given GP, with common ratio as 8 and first term as 63
The Nth term,when N=3,4,5 - - - - - - (For N=1,2 known)
a(N)= (63) * ( 8^(N-3) )
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