Question

In an insulated container 1 mole of a liquid. molar
volume 100 ml at 1 bar. Liquid is steeply taken to
100 bar, when volume of liquid decreases by 1 ml.
Find AH for the process.
1) 7900 bar ml 2) 8900 bar ml
3) 9900 bar ml 4) 10900 bar ml​

Answer 1

Answer:

(3)

Explanation:

Refer image :ΔH by some reaction that happend inside is used for :

(a)increasing internal energy of gas due to which pressure exists. and,

(b)work done to decrease volume of liquid.

Hope it helps.........!

Answer 2

Answer:

Here you go ..........

Explanation:

given that 100ml of liquid was initially at 1bar and the volume becomes 99ml when pressure was increased to 100bar

ΔH = ΔU + ΔPΔV

ΔU = q + w

      = 0 + -P(external pressure) x ΔV

       = -100(99-100)

       =  -100(-1)

       =   100bar ml

Now ΔH = ΔU + (P2V2 - P1V1)

               = 100 + {100(99) - 1(100) }

               = 100 + 9900 - 100

               = 9900bar ml

Hope you will find this helpful.

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