in an intensity pattern with two coherent sources the amplitude of intensity variations is found to be 5% of the average intensity. Calculate the relative intensities of the interfering sources.
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Answer:
I
min
I
max
=
(a−1)
2
(a+1)
2
where amplitude ratio of two sources is assumed to be a:1
Let the average intensity be 100 units, then I
max
=105 units and I
min
=95 units
95
105
=
(a−1)
2
(a+1)
2
which gives a=40
therefore,
I
min
I
max
=
1
1600
Explanation:
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