Question

in an inter barangay basketball league the team from hermana fausta has won 12 out of 25 games a winning percentage of 48% we have seen that they need to win 8 games consecutively to raise their percentage if they win 10,20,30,50,100 games? ( hint: try to subtitute 300 games). write your interpretation​

Answer 1

$\huge \bf \green \{question \green \}$

in an inter barangay basketball league the team from hermana fausta has won 12 out of 25 games a winning percentage of 48% we have seen that they need to win 8 games consecutively to raise their percentage if they win 10,20,30,50,100 games?

$\huge \bf \green \{solution \green \}$

when they win 10 matches

percentage = (12 + 10)/(25 + 10)

= 22/35

= .6285..

or appr 62.9 %

when they win 20 matches

percentage = (12 + 20)/(25 + 20)

= 32/45

= .0.71

or 0.71 appr %

when they win 30 matches

percentage = (12 + 30)/(25 + 30)

= 42/55

= .0.7

or 0.76 appr %

when they win 50 matches

percentage = (12 + 50)/(25 + 50)

= 62/75

= .0.8

or 0.9appr %

when they win 100 matches

percentage = (12 + 100)/(25 + 100)

= 112/125

= .0.8

0.9 appr %

Answer 2

(A) when they win 10 matches:

percentage = (12 + 10)/(25 + 10)

= 22/35

= 0.6285.

or

appr 62.9 %

(B) when they win 20 matches:

percentage = (12 + 20)/(25 + 20)

= 32/45

= .0.71

or 0.71 appr %

(C) when they win 30 matches:

percentage = (12 + 30)/(25 + 30)

= 42/55

=0 .0.7

or 0.76 appr %

(D) when they win 50 matches:

percentage = (12 + 50)/(25 + 50)

= 62/75

= .0.8

or 0.9appr %

(E) when they win 100 matches:

percentage = (12 + 100)/(25 + 100)

= 112/125

= .0.8

0.9 appr %