Question

In an interference pattern at a point, we observe the 12th order maximum for wavelength
600 nm. What order will be visible here if the source is replaced by light of wave
length 480 nm
​

Answer 1

Answer:

The distance of a bright fringe from zero order fringe I s given by-

<br> D&d is constant <br>

<br>

Answer 2

Given,

Wavelength of 12th order maxima 600nm

To Find,

Order for wavelength 480 nm.

Solution,

For the interference pattern we have the formula that,

y=(n×lambda×D)/d

So for this question D and d are equal.

12×600×D/d = n×480×D/d

⇒n = 12×600/480

⇒n = 15

Hence, 15th order will be visible here of the source is replaced by light of wave length 480nm.