Question

In an intrinsic semiconductor band gap is 1.2 ev. The ratio of number of charge carriers at 600k and 300k is

Answer 1

Dear Student,

◆ Answer -

n1/n2 = 1.091×10^-5

● Explanation -

No of charge carriers at temperature 300 K is -

n1 = no × e^(-Eg/2KT1)

No of charge carriers at temperature 600 K is -

n2 = no × e^(-Eg/2KT2)

Ratio of n1/n2 is -

n1/n2 = [no.e^(-Eg/2KT1)] / [no.e^(-Eg/2KT2)]

n1/n2 = e^[Eg (1/T1 - 1/T2) / 2K]

n1/n2 = e^[1.2 × (1/300-1/600) / (2×8.62×10^-5)]

n1/n2 = e^[1.2/(600 × 17.24×10^-5)]

n1/n2 = e^11.6

n1/n2 = 1.091×10^-5

Hence, ratio of number of charge carriers at 600k and 300k is 1.091×10^-5.

Thanks dear.

Answer 2

Answer:

Hence, ratio of number of charge carriers at 600k and 300k is 1.091×10^-5.