Question

In an ionic crystalline solid atoms of element Y form hcp lattice. The atoms of element X occupy one third of tetrahedral voids. What is the formula of the compound ? (X2Y3)

Answer 1

Answer:

Let the number of Y atoms in hexagonal close packing be x.

Number of tetrahedral voids =2x

Number of X atoms =

3

2

×2x=

3

4

x

Ratio of X and Y=

3

4x

:x=4:3

∴ Formula of the compound is X

4

Y

3

.

Answer 2

Answer:

Let the number of Y atoms in hexagonal close packing be x.

Number of tetrahedral voids =2x

Number of X atoms =

3

2

×2x=

3

4

x

Ratio of X and Y=

3

4x

:x=4:3

∴ Formula of the compound is X

4

Y

3

Explanation:

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