Question

in an iscolecs triangle ABC with. AB=AC the bisectors of angel B and angel C intersect at o join a to o show that ob=oc

Answer 1

In triangle ABC

AB=AC

SO,angleABC=angleACB

AS, BO and CO are bisector.

so,angleOBC=angleOCB

therefore, OB=OC                 (side opposite to equal angle are equal)

Answer 2

Step-by-step explanation:

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Solution:-

Given:-

AB = AC and

the bisectors of B and C intersect each other at O

(i) Since ABC is an isosceles with AB = AC,

B = C

½ B = ½ C

⇒ OBC = OCB (Angle bisectors)

∴ OB = OC (Side opposite to the equal angles are equal.)

(ii) In ΔAOB and ΔAOC,

AB = AC (Given in the question)

AO = AO (Common arm)

OB = OC (As Proved Already)

So, ΔAOB ΔAOC by SSS congruence condition.

BAO = CAO (by CPCT)

Thus, AO bisects A.

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