Question

in an iscosceles trapezoid the length of a diagonal is 25 cm and the length of an altitude is 15 cm. find the area of the trapezoid

need answer asap pls

Answer 1

Answer:

draw the sketch. label the top base a, the bottom c.

now notice on c, it is longer than a by 2*k, where k is the length of the base below end triangles.

Pyth: (c-k)^2=25^2-15^2

or c-k=20cm

but c=a+2K

Now the median length:

median=(a+c)/2=(c-2k+c)/2

=2c-2k=2(c-k)=20cm

area=median*height=20cm*15cm

=300cm^2

Answer 2

Step-by-step explanation:

you need the bases first.

draw the sketch. label the top base a, the bottom c.

now notice on c, it is longer than a by 2*k, where k is the length of the base below end triangles.

Pyth: (c-k)^2=25^2-15^2

or c-k=20cm

but c=a+2K

Now the median length:

median=(a+c)/2=(c-2k+c)/2

=2c-2k=2(c-k)=20cm

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area=median*height=20cm*15cm

=300cm^2