in an isobaric process when 2000J of heat energy is supplied to a gas in a cylinder,the piston of area 2.0×10exponent-2 moves through 40cm under a pressure of 1.01×10exponent5.calculate the increase in internal energy of the system
Answers
Answered by
0
Answer:
ΔU=Q−W [From !st law of thermodynamics]
Q=200J
W=100J
∴ΔU=(200−100)J=100J
Answered by
3
Explanation:
ΔU=Q−W [From !st law of thermodynamics]
Q=200J
W=100J
∴ΔU=(200−100)J=100J
Similar questions