Question

In an isoceles triangle each base angle is 30° greater than the vertical angle.Find the measure of all the three angles of the triangle

Answer 1

let the vertex be X; base angle = X + 30°

X+30 + X+30 + X = 180°

3x + 60 = 180°

3x = 180 - 60

X = 120/3

X = 40°

Base angles = X + 30°
= (40) + 30°
= 70°
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so, the three angles are 40°, 70° & 70°
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Answer 2

$\boxed{\bf{SOLUTION}}$

Let the measure of unknown angle be x°.

Since the ∆ ABC is an isosceles∆.

Therefore, Angle B = angle C

As per question...

Angle B=Angle C = 30°+x

Therefore by Angle Sum Property of ∆.

(30+x)+(30+x)+x=180°

=> 30+x+30+x+x = 180°

=> 60+3x = 180°

=> 3x = 180–60

=> 3x = 120

=> x= 40°

Therefore, angle A = 40°

angle B = 30°+40°

= 70°

angle C = 70°

#BE BRAINLY