Question

in an isoceles triangle if the vertex angle is twice the sum of base angles.​

Answer 1

Step-by-step explanation:

Let each base angle be x in an isosceles △ABC

Then vertex angle be 2(x+x)=4x

Since sum of angles of a triangle is 180

o

.

Hence 4x+x+x=180

o

⇒6x=180

0

⇒x=30

0

∴ Angles are 30

o

,30

o

,120

o

Answer 2

Answer:

let base angles of triangle =x

x+x×(2)=180 because all angles of a triangle is 180°

2x×2=180

2×2×=180

4x=180

x=180/4

x=45°