Math, asked by haizatwiliht, 2 months ago

in an isoceles triangle the base angles are equal.the vertex angle is 40 degree.what are the base angles of the trinagle

Answers

Answered by krahul3020
1

Answer:

base angle=70 degree

Step-by-step explanation:

Solution: let base angle =x

vertex angle=40 degree

sum of angle of triangle=180

x+x+40=180

2x=180-40

2x=140

x=70

so base angle=70 degree

Answered by pro111to
0

Step-by-step explanation:

Vertex angle = 40°

Let one of the base angle be (x)°. So second base angle = (x)° (In an isosceles triangle the base angles are equal)

40+x+x=180 (Angle Sum Property of a Triangle)

=40+ 2x=180

=2x=140

=x= 70°

Hence the base angles are 70° each.

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