Question

In an isoceles triangle the vertex Angele is twice the base angle find the vertex Angele

Answer 1

Answer:

90°

Step-by-step explanation:

Consider ∆ABC with AB=AC.

If AB=AC, then angle ABC=angleACB

Let angle ABC = angle ACB = x°

Then Vertex angle=angle BAC=2x°

angle ABC + angle ACB + angle BAC = 180°

(Angle Sum Property)

x+x+2x=180°

4x=180°

x=180°/4

x=45°

Thus, Vertex angle = 2x = 2×45° = 90°

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