Math, asked by gsaikia5611, 1 year ago

In an isoceles triangle the vertical angle is 18 less than a base angle find the measure of base angle of the triangle

Answers

Answered by TPS
0
Let the two base angles be x each

vertical angle = x-18

sum of angles = 180

=> x + x + x-18 = 180

=> 3x = 180 + 18 = 198

=> x = 198/3

=> x = 66°

x - 18 = 66 - 18 = 48°

Angles are 66°, 66° and 48°
Answered by Brainlyconquerer
0
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Let angles be x

⏩vertical angle = x-18

⏩sum of angles = 180

⏩ x + x + x-18 = 180

⏩3x = 180 + 18 = 198

⏩x =  \frac{198}{3}

⏩ x = 66°

x - 18 = 66 - 18

⏩48°

So,

Angles are 66° 66° and 48°

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