In an isoceles triangle the vertical angle is 18 less than a base angle find the measure of base angle of the triangle
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Let the two base angles be x each
vertical angle = x-18
sum of angles = 180
=> x + x + x-18 = 180
=> 3x = 180 + 18 = 198
=> x = 198/3
=> x = 66°
x - 18 = 66 - 18 = 48°
Angles are 66°, 66° and 48°
vertical angle = x-18
sum of angles = 180
=> x + x + x-18 = 180
=> 3x = 180 + 18 = 198
=> x = 198/3
=> x = 66°
x - 18 = 66 - 18 = 48°
Angles are 66°, 66° and 48°
Answered by
0
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☬ YOUR ANSWER ☬
╘═════════════════════╛
Let angles be x
⏩vertical angle = x-18
⏩sum of angles = 180
⏩ x + x + x-18 = 180
⏩3x = 180 + 18 = 198
⏩x =
⏩ x = 66°
x - 18 = 66 - 18
⏩48°
So,
Angles are 66° 66° and 48°
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
☬ YOUR ANSWER ☬
╘═════════════════════╛
Let angles be x
⏩vertical angle = x-18
⏩sum of angles = 180
⏩ x + x + x-18 = 180
⏩3x = 180 + 18 = 198
⏩x =
⏩ x = 66°
x - 18 = 66 - 18
⏩48°
So,
Angles are 66° 66° and 48°
╒══════════════════════╕
☬ THANKS! @Brainlyconquerer ☬
╘══════════════════════╛
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