Question

In an isochoric process system absorb 500J at 1x10 Nm pressure and 500cm' volume what is
change in ΔΕ: :

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Answer 1

Answer:

In the process AB we have

work done is zero (isochoric process)

Using First law we get

ΔU=ΔQ−0=600J

In the process BC the work done is calculated as

PΔV=8×10

4

×3×10

−3

=240J

Thus we get ΔU=200−240=−40J

Thus the total change in internal energy is given as

600−40=560J