Math, asked by TheEshan, 11 months ago

In an Isocles triangle, I the base angles are equal. The vertex angle is 40•. What are the base angles?​

Answers

Answered by trupti1289
1

Step-by-step explanation:

Given: Vertex angle= 40°

Since ∆ is an iso.∆

Base angle are equal.

Let base angle be x.

By angle sum prop to ∆

Two base angle + vertex angle=180°

2x + 40=180

2x = 180-40

2x = 140

x= 140/2

x= 70°

The base angle of is 70°...

Hope it helps you...

Answered by ashit1234kol
1

Answer:

The base Angle would be 70 each

Step-by-step explanation:

Given that

Vertex angle = 40 °

Another thing it is isosceles triangle

That means bases will have equal angle

Now from

Angle Sum Property of Triangle

Angle(A+B+C)=180°

Angle(40°)+Angle(B+C)=180°

Angle(B+C) =140°

That means

Angle B = 70°

And

Angle C=70°

Hope it Could Help u

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