Question

in an isolceus triangle length of congurent sides is 13cm and base is 10cm find distance between ​

Answer 1

Answer:

Area of triangle = [18(18–13)(18–13)(18–10)}^0.5 = [18*5*5*8]^0.5 = 60 sq cm. Altitude of the triangle = 60*2/10 = 12 cm.

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