Question

In an isoscales triangle ABC, AB=AC. Prove that the median AD which meets BC at D is also the perpendicular bisector of BC. ​

Answer 1

Answer:

Ans4.In isosceles Triangle ABC

AB= AC [given]

Property of isosceles triangle.

AD = AD [ common]

Thus

Thus BD= CD [BY CPCT]

By CPCT

Now to prove that AD is a perpendicular bisector of BC,we have to prove with the help of linear pair

Hence proved.

Ans 5.

(a) ∆ABC ≈ ∆DBC

AB = DC [Given]

BC = BC [common]

By AAS CRITERION OF CONGRUENCY OF TRIANGLE ,

(ii) If two triangles are congruent than corresponding parts are equal, thus

by CPCT.

(iii) In ∆ AOB and ∆DOC

Thus by AAS CRITERION OF CONGRUENCY OF TRIANGLES,

(iv) Since ∆AOB and ∆ DOC are congruent,so

BO= CO (BY CPCT)

Thus ∆OBC is Isosceles.

Hope it helps you.

please mark as brain list

and follow me

Answer 2

hope this attachment will be helpful to you

mark as brainlest answer please