in an isoscales triangle ABC WITH AB=AC,D and E are points on BC such that BE = CD. prove that AD = AE
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GIVEN A ΔABC in which AB=AC. D and E are point on BC such that BE=CD.
TO PROVE AD = AE.
PROOF BE=CD⇒BE−DE=CD−DE
⇒BD=CE.
Now, in ΔABDandΔACE, we have
AB=AC (given),
∠B=∠C [angles opposite to equal sides]
and BD=CE [proved above in (i)].
∴ ΔABD≅ΔACE (SAS-criteria).
Hence, AD=AE (c.p.c.t.).
Hope it helps :D
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