Math, asked by mystery52, 6 months ago

In an isosceles A ABC, AB = AC and AD, BE, CF are perpendicular to its sides BC, AC and AB respectively.
Name the perpendicular about which the triangle is symmetrical​

Answers

Answered by khashrul
1

Answer:

ΔABC is symmetrical around perpendicular AD.

Step-by-step explanation:

Between ΔABD and ΔACD:

AD is common side, AB = AC [Given]

∠ADB = ∠ADC [Given that AD ⊥ BC]

∴ ΔABD and ΔACD are congruent.

∴ ΔABC is symmetrical around perpendicular AD.  

Similar questions