In an isosceles A ABC, AB = AC and AD, BE, CF are perpendicular to its sides BC, AC and AB respectively.
Name the perpendicular about which the triangle is symmetrical
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Answer:
ΔABC is symmetrical around perpendicular AD.
Step-by-step explanation:
Between ΔABD and ΔACD:
AD is common side, AB = AC [Given]
∠ADB = ∠ADC [Given that AD ⊥ BC]
∴ ΔABD and ΔACD are congruent.
∴ ΔABC is symmetrical around perpendicular AD.
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