Question

In an isosceles ∆ ABC, the bisectors of B and C meet at a point O. If A = 40° , then BOC = ?
please show the method I know the answer is 110° but don't know the method​

Answer 1

Answer:

Step-by-step explanation:

angle BOC Will be 110°.

1 . in an isosceles triangle 2 angles are equal so

A+B+C=180°[angle sum prop.]

40°+B+B=180°[since B=B]

40°+2B=180°

2B=180°-40°=140°

B=140°/2=79°

there fore A=40°,B=C=70°

as CO biscets C then OCB=35°. [half of C]

and OBC=35°[half of B]

OCB+OBC+BOC=180°

35°+35°+BOC=180°

70°+BOC=180°

BOC=180°-70°=110°