Question

in an isosceles ∆ABC the measure of vertex angle A is 30° more than the measure of each base angle. Find the measure of each angle of triangle ​

Answer 1

Answer:

Hope it is helpfull for you!!!!

Answer 2

Step-by-step explanation:

Let the two base angle be x.

so angle A = x + 30°

angle A + angle B + angle C = 180° ( angle sum

property of a

triangle)

= (x + 30°) + x + x = 180°

= x + x + x + 30° = 180°

= 3x = 180° - 30°

= 3x = 150°

= x = 150°/3

= x = 50°

So, x = angle B = angle C = 50°

angle A = x + 30°

= 50° + 30°

= 80°

Therefore, angle A = 80°

angle B = 50°

angle C = 50°