In an isosceles ∆ABC with AB = AC and angle BAC = 100o ; if the bisectors of base angles angle B and angle C meet at point O then angle BOC will be ?
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Answer:given- angle BAC =100
Base angles = 100+2x= 180
2x=80
X=40
Now both base angles are bisected therefore 40/2 + 40/2 + y =180
20+20+y=180
Y=140
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