Question

in an isosceles agle. each base angle is four time its vertcle angle.find each angle of the triangle.

Answer 1

Let the vertex angle be x

base angles are 4x each

sum of angles = 180

=> x + 4x + 4x = 180

=> 9x = !80

=> x = 180/9 = 20°

4x = 20×4 = 80°

Angles are 20°, 80° and 80°

Answer 2

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⏩let the vertex angle = x

angles are 4x

⏩sum of angles = 180

⏩x + 4x + 4x = 180

⏩9x = 80

⏩x = 180/9 = 20°

⏩4x = 20×4 = 80°

Angles are 20°, 80° and 80°

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