Math, asked by gouthamidasi, 3 months ago

In an isosceles ∆PQR, PR=QR and PQ²=2PR², then ∠R=​

Answers

Answered by januu36
0

Step-by-step explanation:

ANSWER

As ΔPQR is right angled at R, then,

PQ

2

=QR

2

+PR

2

Since the triangle is an isosceles triangle, then, QR=PR, therefore,

PQ

2

=PR

2

+PR

2

PQ

2

=2PR

2

Hence proved.

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