In an isosceles ∆PQR, PR=QR and PQ²=2PR², then ∠R=
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Step-by-step explanation:
ANSWER
As ΔPQR is right angled at R, then,
PQ
2
=QR
2
+PR
2
Since the triangle is an isosceles triangle, then, QR=PR, therefore,
PQ
2
=PR
2
+PR
2
PQ
2
=2PR
2
Hence proved.
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