In an isosceles PQR, where PQ = PR, the bisectors of ∠PQR and ∠PRQ meet at a point O.
If ∠QPR = 80° then find the measure of ∠QOR.
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Answered by
14
Answer:
∠QPR=80°
∠PQR+∠QPR+∠QRP=180°
∠PQR+∠QRP=100°
2(x+y)=100°
x+y=50°
So, in △QOR
x+y+∠QOR=180°
∴∠QOR=180°−50°
=130°
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Answered by
6
Answer:
ans is 130 if you want the QOR which is inside triangle QOR
if you Want the angle QoR which is outside the triangle QOR
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